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Rainbow [258]
3 years ago
8

Round 1,287 to the nearest thousands place

Mathematics
2 answers:
Dmitry [639]3 years ago
5 0

Answer:

1,000

Step-by-step explanation:

refer to attached.

the number in the thousands place is the number 1.

How we round this number depends on the number immediately to the right of it (i.e the hundreds number)

Case 1: If the number in the hundreds place is less than 5, then we keep the number in the thousands place the same and replace all the digits to the right of the thousands digit by zeros

Case 2: If the number in the hundreds place is 5 or more, then increase the number in the thousands place  by 1 and replace all the digits to the right of the thousands digit by zeros

in our case, the hundreds digit is 2, which falls into case 1 above,

hence according to the procedure in case 1 above, we keep number 2 the same and replace everything to the right of 2 with zeros, giving us

1,000

alexdok [17]3 years ago
3 0

Answer:

1000

Step-by-step explanation:

If a number is higher than 5 round up. If its 4 or lower round down

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3 years ago
For a-b, reduce to the least non-negative residue
Olenka [21]

Answer:

  a.  6

  b.  9

Step-by-step explanation:

a. The product modulo 7 can be found from the product of the individual numbers modulo 7:

  (88·95·36·702) mod 7 = (88 mod 7)·(95 mod 7)·(36 mod 7)·(703 mod 7) mod 7

  = (4·4·1·3) mod 7 = 48 mod 7 = 6

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b. Powers of 4 mod 11 repeat with period 5:

  4 mod 11 = 4

  4^2 mod 11 = 5

  4^3 mod 11 = 9

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3 0
3 years ago
Iterations question two need help please :)
Contact [7]

Answer:

option b

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Step-by-step explanation:

Given in the question a function, f(x) = (x - 5)²

initial value x_{0} = 4

First iteration

f(x0) = f(4) = (4 - 5)² = (-1)² = 1

x1 = 1

Second iteration

f(x1) = f(1) = (1 - 5)² = (-4)² = 16

x2 = 16

Third iteration

f(x2) = f(16) = ( 16 - 5)² = (11)² = 121

x3 = 121

Fourth iteration

f(x3) = f(121) = (121 - 5)² = (116)² = 13456

x4 = 13456

 

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3 years ago
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valentinak56 [21]
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