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2 years ago

Is DE parallel to AB? Show your work to receive full credit.

Mathematics

1 answer:

Svetllana [295]2 years ago

8 0

Answer:

DE is parallel to AB, ∠ACB =∠DCE. So from symmetry of triangle. Δ DCE and Δ ABC are symmetric

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25+29=9v solve for v

Natasha_Volkova [10]

The answer is V= 6 :)

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2 years ago

Read 2 more answers

The table below represents the function F. 3 7 F(x) 4 15 5 31 7 127 8 255 The equation that represents this function is?

timurjin [86]

The table is an exponential function, and the equation that represents this function is $f(x) =2^x -1$

<h3>The equation of the table</h3>

The table is given as:

x F(x)

4 15

5 31

7 127

8 255

Rewrite the table as:

x F(x)

4 16 - 1

5 32 - 1

7 128 - 1

8 256 - 1

Express as a base of 2

x F(x)

4 2⁴ - 1

5 2⁵- 1

7 2⁷ - 1

8 2⁸ - 1

Notice that the function is 1 subtracted from 2 raised to the power of the input.

This is represented as:

$f(x) =2^x -1$

Hence, the equation of the table is $f(x) =2^x -1$

Read more about exponential functions at

brainly.com/question/9608962

#SPJ1

4 0

1 year ago

Hi guys can someone please help me with these questions please

Zinaida [17]

Hi There!

----------------------------------

Question 2:

Obviously the right equation for this question is Point Slope Form.

Point Slope Form: y - y1 = m(x - x1)

y1 = -1

x1 = 3

m = 2

Question 2 Answer: y + 1 = 2(x - 3)

----------------------------------

Question 3:

Again use point slope form.

Find Slope:

7 - 1 = 6

-2 - 1 = -3

6/-3 = -2

Question 3 Answer: y - 1 = -2(x - 1)

----------------------------------

Hope This Helps :)

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3 years ago

P what equation in slope-intercept form represents the line that passes through the points (3,5) and (-9,2)

ivanzaharov [21]

Answer:

$y =\frac{1}{5}x+\frac{22}{5}$

Step-by-step explanation:

To write the equation of a line, use the slope formula to first find the slope.

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{3--9}=\frac{3}{3+12}=\frac{3}{15}=\frac{1}{5}$

Substitute m=1/5 and the point (3,5) into point slope formula.

$y-y_1 = m(x-x_1)\\y-5=\frac{1}{5}(x-3)\\y-5=\frac{1}{5}x -\frac{3}{5}\\y =\frac{1}{5}x+\frac{22}{5}$

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3 years ago

Help asap, please!!!!!!!!

Artemon [7]

1/6p + (-4/5) is the equivalent expression. You have to add like terms, meaning constants are added to constants, variables are added to variables, etc. the result you get from adding like variables leaves you with 1/6p + (-4/5) or 1/6p - 4/5

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2 years ago