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Bogdan [553]
2 years ago
7

Is DE parallel to AB? Show your work to receive full credit.

Mathematics
1 answer:
Svetllana [295]2 years ago
8 0

Answer:

DE is parallel to AB, ∠ACB =∠DCE. So from symmetry of triangle. Δ DCE and Δ ABC are symmetric

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Triangle ABC had a perimeter 18 cm
Anna007 [38]

Answer:

Use pythagoreum theorem to determine whether it is or isn't since I'm not really sure myself but here's my calculations.

Step-by-step explanation:

We need to find AC.

Picture a triangle called ABC. AB is one side and BC the other while AC is the hypotenuse.

AC=

ac =  \sqrt{ab ^{2}  +  {bc}^{2} } \\ ac = \sqrt{ {7}^{2} }  +  {3}^{2}  \\ ac =  \sqrt{49 + 9}  \\ ac =  \sqrt{58 }  \\ ac = 7.6

Round up the 7.6 to a whole number and you get AC=8. To get perimeter of a triangle simply add the sides together to get 18.

Not really sure about my answer but hope this helped.

5 0
2 years ago
Whats 2.13×0.197 as a decimal
Tcecarenko [31]

Answer:

It's 0.41961.

8 0
3 years ago
Read 2 more answers
What is 1 times 1? Please answer because I need this due in 15 minutes
Sonbull [250]

Answer:

1

Step-by-step explanation:

1*1=1

thats it tbh

8 0
3 years ago
Read 2 more answers
Solve the equation for x in terms of c
Dovator [93]

solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}

\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}

\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}

\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}

\mathrm{Multiply\:both\:sides\:by\:}3

3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}

2cx+1=\frac{33}{4}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

2cx+1-1=\frac{33}{4}-1

2cx=\frac{29}{4}

\mathrm{Divide\:both\:sides\:by\:}2c

x=\frac{29}{8c}

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>
8 0
3 years ago
A 20 foot ladder is leaning up against the side of a house the distance between the house and the base of the ladder is 4 feet f
Pie

Answer:

78.5°

Step-by-step explanation:

We solve for the above question, using the formula for the Trigonometric function of Cosine

cos θ = Adjacent/Hypotenuse

Adjacent = The distance between the house and the base of the ladder = 4 feet

Hypotenuse = Length of the Ladder = 20 feet

Hence,

cos θ = 4/20

θ = arc cos(4/20)

θ = 78.463040967°

Approximately = 78.5°

Therefore, the angle that the ladder makes with the ground is 78.5°

6 0
2 years ago
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