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3 years ago

Find the equation of the line.

Mathematics

1 answer:

docker41 [41]3 years ago

7 0

Answer:

Step-by-step explanation:

the slope of the line perpendicular is -8 (negative recriporal of line)

substitue (3,5) in equation: y = -8x+b

5 = -24+b

b = 29

the equation is y = -8x+29

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Please explain also

Katena32 [7]

Answer:

300 m^2

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask =)

3 0

3 years ago

If D varies directly with t and D is 105 when t is 3, find D when t is 8.<br><br> 35<br> 280<br> 840

drek231 [11]

Answer:

280

Step-by-step explanation:

D = kt

105 = 3k

k = 35

D = 35t

D = 35(8) = 280

5 0

4 years ago

Read 2 more answers

Solve the systems by the addition method x - 2y = - 4 2x + y = 7

vfiekz [6]

To solve this system of equations by addition, our first goal is to cancel

out one of the variables by adding the two equations together.

However, if we add these two equations together right away, nothing

will cancel so we need to set things up so a variable will cancel.

Notice that we have an 2x in our second equation.

If we had a -2x in our first equation, then the x's would cancel out.

In order to create a -2x in the first equation, we simply

multiply both sides of the first equation by -2.

So we have (-2)(x - 2y) = (-4)(-2) which can be rewritten as -2x + 4y = 8.

Now rewrite both equations, as shown below.

Now when we add the equations together, the x terms

will cancel out and we're left with 5y = 15.

Dividing both sides by 5, <em>y = 3</em>.

To solve for x, plug a 3 in for y in either one of our 2 original equations.

So let's go with our second equation.

Plugging a 3 in for y, we get 2x + (3) = 7.

Now subtract 4 from both sides to get 2x = 4.

Dividing both sides by 2, we fid that <em>x = 2</em>.

Since x = 2 and y = 3, our answer is the ordered pair (2, 3).

5 0

3 years ago

2. If m <1 = 43, what is m <4?

Alex17521 [72]

I do need help please

6 0

4 years ago

I need help with this

andre [41]

Answer:

$f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}$

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

Taken altogether, these factors give us the function ...

$\boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}$

8 0

3 years ago