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larisa86 [58]
3 years ago
13

Claire McCullough got her water and sewer bill from Dynamo Water & Wastewater Company which showed the following uses of wat

er and sewer: water usage = 42 HCF; sewer usage = 31 HCF. Given the information below, what was the Claire's total monthly water and sewer bill? Dynamo Water & Wastewater Company has the following bi-monthly (every two months) rates for water and sewer usage: Water: Water Base Fee: $39.51 Water Usage (at or below 30 HCF): $3.76 per HCF Water Usage (above 30 HCF): $4.95 per HCF Sewer: Sewer Base Fee: $31.87 Sewer Usage Fee: $3.88 per HCF of water use Storm Drain Fee: $6.79
Mathematics
1 answer:
ioda3 years ago
7 0

Answer:

Step-by-step explanation:

C

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Very easy! 15 points!
Irina-Kira [14]

Answer:

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Nvm i just got the question done
Alecsey [184]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
The slope of a line is -1/4 and the y-intercept is 8. Whats the x-intercept?
Fed [463]
Slope = -1/4
y-interept = 8
⇒equation:  y = -1/4x + 8

x-intercept ⇒ when y = 0
0 = -1/4x + 8
1/4x = 8
x = 8 x 4 
x = 32

Answer: x-intercept = (32,0)
7 0
2 years ago
The cones below are similar, although not drawn to scale.
Dmitry [639]
9 ft
Set up a ratio...6/18=x/27...reduce to 1/3=x/27...cross multiply and solve for x.
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5 0
2 years ago
Read 2 more answers
Evaluate each trigonometric equation for θ.
liberstina [14]

Answer:

sinФ = 8/17

cosФ = 15/17

tan Ф = 8/15

csc Ф = 17/8

sec Ф = 17/15

cot Ф = 15/8

Step-by-step explanation:

Let us revise the trigonometry functions

  • Sin(x) = opposite/hypotenuse
  • Cos(x) = adjacent/hypoteouse
  • Tan(x) = opposite/adjacent
  • Csc(x) = hypotenuse/opposit
  • Sec(x) = hypotenues/adjacent
  • Cot(x) = adjacent/opposite

In the given figure

The opposite side to angle Ф = 8

The adjacent side to angle Ф = 15

Find the hypotenuse using Pythagoras' theorem

Hypotenuse = \sqrt{8^{2}+15^{2}  }

Hypotenuse = \sqrt{64+225}

Hypotenuse = \sqrt{289}

Hypotenuse = 17

Let us use the rules above to find the trigonometry functions

sinФ = 8/17

cosФ = 15/17

tan Ф = 8/15

csc Ф = 17/8

sec Ф = 17/15

cot Ф = 15/8

4 0
3 years ago
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