Answer:
(221.39, 300.61) and (255.2223, 266.7777)
Step-by-step explanation:
Given that X, the lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days
Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0
Corresponding we have x scores as
Between 
and 
i.e. in the interval = (221.39, 300.61)
If sample size = 47, then std error of sample would be
So 98% of pregnancies would lie between
and 
= (255.2223, 266.7777)
Answer:
1. 13+18+13+14+13+16+14+21+13
= 145/9
=16.11
2. Range =145
3. Mode =13
4. Median =14
Step-by-step explanation:
Answer:
1. P(5 U 6) =2/3
2. P(2 U 5 U 6) = 5/6
3. P(1 U 2) = 1/3
4. P(4) = 0
Step-by-step explanation:
As the number cube has 6 sides,
So,
Total outcomes = {1,2,5,5,6,6}
n(S) = 6
Now,
1. P(5U6) = P(5) + P(6)
P(5)=2/6=1/3
P(6)=2/6=1/3
P(5U6)= 1/3 + 1/3 = 2/3
2. P(2 U 5 U 6) = P(2) + P(5) + P(6)
P(2)=1/6
P(5)=2/6
P(6)=2/6
P(2 U 5 U 6) = 1/6 + 2/6 + 2/6
= 5/6
3. P(1 U 2) = P(1) + P(2)
P(1) = 1/6
P(2)= 1/6
P(1 U 2) = 1/6 + 1/6
= 2/6 = 1/3
4. P(4) = 0
As 4 is not in the outcomes, it's probability will be zero ..
Answer: a=36; b=18
Step-by-step explanation:
1. You know that the sum of two numbers is 54, then, you have:
a+b=54
2. According to the problem, the larger number is 18 more than the sampler number, this can be expressed as following:
a=b+18
3. Then, you must substitute the second equation into the first equation and solve for b:
b+18+b=54
b=18
4. Then the value of a is:
a+18=55
a=36
