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4 years ago

At 1pm, there was 16 seagulls on the beach. At 3pm, there were 60 seagulls. What is the constant rate of change

Mathematics

2 answers:

belka [17]4 years ago

7 0

22 seagulls per hour... cx

rodikova [14]4 years ago

7 0

1/3 = 16/60
Cross Multiply
48/60=4/5
The constant rate of change is 4/5

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What is the length of BC in the right triangle below?

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Answer:

b. 98

Step-by-step explanation:

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3 years ago

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You are doing annual inventory at the hardware store where you work. A box filled with brass connectors weighs 5 pounds 4 ounces

Georgia [21]

Answer:

304 brass connectors.

Step-by-step explanation:

We have been given that a box filled with brass connectors weighs 5 pounds 4 ounces. The box weighs 8 ounces when empty, and each connector weighs 0.25 ounces.

Since we know that 1 pound equals to 16 ounces.Let us convert weight of box filled with brass connectors from pounds to ounces.

$(5*16)+4=80+4=84$

Now we will find weight of brass connectors by subtracting weight of empty box from weight of filled box.

$84-8=76$

Let us divide 76 by 0.25 to find number of brass connectors in the box.

$\text{ Number of brass connectors in the box}=\frac{76}{0.25}$

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Therefore, there are 304 connectors in the box.

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4 years ago

The mean lifespan of a sylvania light bulb is 1600 hours with a standard deviation of 300 hours, an iqr of 450 hours, and a rang

IgorLugansk [536]

Given that t<span>he mean lifespan of a sylvania light bulb is 1600 hours with a standard deviation of 300 hours, an iqr of 450 hours, and a range of 690 hours. the lifespan distribution is relatively symmetric.

Since, the distribution is relatively symmetric, the measure of spread that is the best measurement is the standard deviation.</span>

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3 years ago

Find the solution of this system of equations:

Evgen [1.6K]

Answer:

y=-3.667

Step-by-step explanation:

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4 years ago

About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number

olganol [36]

Answer:

1) $E(X) = np = 120*0.1 =12$

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

2) $P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

$X\sim Binom(n= 120 , p =0.1)$

Part 1

The mean is given by:

$E(X) = np = 120*0.1 =12$

And the deviation would be:

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

$P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

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3 years ago