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prohojiy [21]
3 years ago
15

Which of the following are equations for the line shown below? Check all that apply. O A. y=-3x-3 O B. y+ 5= 3(x- 1) O C. y= 3x-

2 O D. y-4 = 3(x+ 2)

Mathematics
1 answer:
bogdanovich [222]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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A. Mr. Gordon works with Ms. Patel from the Example. Mr. Gordon writes the expression 3x + 4x to represent the cost of ordering
Leviafan [203]

Answer:

$162

Step-by-step explanation:

5r=20 10p=100 14t=42

100+42+20=162

5r+10p+14t=$162

3 0
2 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
EleoNora [17]

Answer:

<h3> X = 2 , X = -3</h3>

Option C is the correct option.

Step-by-step explanation:

f(x) = a {x}^{2}  + bx + c

Discriminant = {b}^{2}  - 4ac

Given d = 15

When discriminant D > 0 --> roots are real and distinct. ( unequal )

So , {3}^{rd} option has real and distinct roots.

Hope this helps..

Best regards!!

4 0
3 years ago
Cody's rent is increasing by $51 per month starting next year. That is an increase of 15% from his current monthly rent. Let r r
Inessa05 [86]

Answer:

r = 43.35

Step-by-step explanation:

Given

Current\ Rent = r

Increment = 15\%

New\ Rent = \$51

Required

Determine the value of r

The value of r can be set up percentage increase formula as follows:

\%Increment  = \frac{New\ Rent - Current\ Rent}{Current\ Rent}

Substitute values in the above equation

15\% = \frac{51 - r}{51}

Cross Multiply

51 - r = 15\% * 51

Convert percentage to decimal

51 - r = 0.15 * 51

51 - r = 7.65

And the value of r\ is\ calculated\ using:

r = 51 -7.65

r = 43.35

Hence, Cody's current rent is $43.35 monthly

8 0
3 years ago
The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Nor
erik [133]

The percentage of young adults send between 128 and 158 text messages per day is; 34%

<h3>How to find the percentage from z-score?</h3>

The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

We are given;

Sample mean; x' = 158

Population mean; μ = 128

standard deviation; σ = 30

We want to find the area under the curve from x = 248 to x = 158.

where x is the number of text messages sent per day.

To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;

z = (x - μ)/σ

z = (158 - 128)/30

z = 30/30

z = 1

This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.

From online p-value from z-score calculator, we have;

P-value = 0.34134 = 34%

Approximately 34% of the the population sends between 128 and 158 text messages per day.

Read more about p-value from z-score at; brainly.com/question/25638875

#SPJ1

4 0
1 year ago
The model below represents an equation. Which value of x makes the equation<br> true?
Sliva [168]

Answer:

1,1,1,1

Step-by-step explanation:

I believe this is right

3 0
2 years ago
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