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Viktor [21]
3 years ago
11

The graph of a proportional relationship is a straight line passing through the?​

Mathematics
2 answers:
Aneli [31]3 years ago
7 0
Through the origin (0,0)
puteri [66]3 years ago
4 0

Answer:

Origin

Step-by-step explanation:

Here you go~

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Write an recursive formula for An, the nth term of the sequence<br> 5, -2, -9,
oksian1 [2.3K]

Given:

The given sequence is:

5,-2,-9,...

To find:

The recursive formula for a_n, the nth term of the sequence.

Solution:

We have,

5,-2,-9,...

Here, the first term is 5.

-2-5=-7

-9-(-2)=-9+2

-9-(-2)=-7

The common difference is -7.

The recursive formula for the nth term of the sequence is

a_n=a_{n-1}+d

Where, d is the common difference.

Putting d=-7 in the above formula, we get

a_n=a_{n-1}+(-7)

a_n=a_{n-1}-7

Therefore, the recursive formula for the nth term of the sequence is a_n=a_{n-1}-7.

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5w²-5w=0 . -10n²+35n=0 . 2x²+15x=0 . 18c²+6c=0 . -32y²-24y=0
love history [14]

5 {w}^{2}  - 5w = 0\Leftrightarrow 5w(w - 1) = 0\Leftrightarrow w = 0 \: \vee \: w = 1 \\  - 10 {n}^{2}  + 35n = 0\Leftrightarrow  - 5n(2n - 7) = 0\Leftrightarrow n = 0 \: \vee \: n =  \frac{7}{2}  \\ 2 {x}^{2}  + 15x = 0\Leftrightarrow x(2x + 15) = 0\Leftrightarrow x = 0 \: \vee \: x =  \frac{15}{2}  \\ 18 {c}^{2}  + 6c = 6c(3c + 1) = 0\Leftrightarrow c = 0  \: \vee \: c =  -  \frac{1}{3}  \\  - 32 {y}^{2}  - 24y = 0\Leftrightarrow  - 8y(4y + 3) = 0\Leftrightarrow y = 0 \:\vee \: y =  -  \frac{3}{4}  \\ 3 {k}^{2}  = 6k\Leftrightarrow k = 0 \: \vee \: k = 2 \\ 6 {h}^{2}  = 3h\Leftrightarrow h = 0 \: \vee \: h =  \frac{1}{2}  \\ 4 {s}^{2}  = 10s\Leftrightarrow s = 0 \: \vee \: s =  \frac{5}{2}  \\  - 42 {z}^{2}  = 14z\Leftrightarrow z = 0 \:\vee \: z =  -  \frac{1}{3}

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4 years ago
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