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Natali [406]
3 years ago
5

Prove algebraically that (m + 2)2 – m 2 – 12 is always a multiple of 4

Mathematics
1 answer:
Julli [10]3 years ago
3 0

Answer:

(m + 2)^{2} - m^{2}  - 12 = 4(m - 2)

Step-by-step explanation:

Step 1:

Write the expression

(m+2)^{2} - m^{2}  - 12

Step 2: Expand (m + 2)^{2}

(m+2)^{2} - m^{2} - 12\\(m+2)(m+2) - m^{2}  - 12\\m^{2} + 2m + 2m + 4 - m^{2}  - 12

Step 3: Collect similar terms

m^{2}  - m^{2}  + 4m + 4 - 12\\4m - 8

Step 4: Factor 4 out of the expression to prove that the expression is a multiple of 4.

Therefore\\4m - 8 = 4(m - 2)\\Hence,\\(m+2)^{2}  - m^{2} -  12 is a multiply of 4 because the expression is equal to 4(m-2)

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I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

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