The zeros of the potynomial y = 3(x + 4)(x + 1)(x - 3)

<h3>Answer: a) -4, -1, 3</h3>
The bigger number is 15 and the smaller number 7. 15 is 8 more than 7. The sum of 15 and 7 is 22.
Hello there! An equation that can be used to find the total cost of the banquet is this:
225 + 50h + 25p = c
This is because "c" represents the total cost of everything, "h" represents hours, and "p" represents people. The $225 paid to rent a hall is a one-time price and does not go up. $50 is paid per hour to the DJ, and $25 is the amount per person for dinner.
Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
Answer:
f(3) = 216
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 6ˣ
x = 3
<u>Step 2: Evaluate</u>
- Substitute: f(3) = 6³
- Exponents: f(3) = 216