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steposvetlana [31]
3 years ago
15

ASAP NO WORK JUST ANSWER

Mathematics
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

c

Step-by-step explanation:

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50% of all the cakes Lucy bakes that week were party cakes: one fifth were fruit cakes and the remainder were sponge cakes. What
dusya [7]
50% is equal to 5/10 so 5/10 were party cakes 1/5x2=2/10 so 2/10 were fruit cakes 5/10+2/10=7/10 so 10/10 which is 100% of all cakes 10/10-7/10=3/10 so 3/10 of the cakes were sponge cakes.
7 0
3 years ago
The corporate team building event will cost $12 if it has three attendees if there are five attendees how much was a quaker team
Norma-Jean [14]

Answer:

Cost to arrange the event for 5 attendees will be $20.

Step-by-step explanation:

We have to solve this question by calculating the unit rates or unitary method.

Since cost to arrange corporate team building event for 3 attendees is = $12

Cost to arrange the event for 1 attendee will be = \frac{12}{3} = $4

Therefore, cost to arrange the event for five attendees will be = 5×4 = $20

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4 years ago
Taylor wants to read 2 books. One book has 232 pages and the other has 184 pages. She needs to return the books to the library i
Norma-Jean [14]
As many as he can if he wants a good grade


5 0
3 years ago
Solve each exponential equation by using properties of common logarithms. When necessary, round answers to the nearest hundredth
lisabon 2012 [21]

Answer:

0.08

Step-by-step explanation:

Please use parentheses to indicate which operations must be done first.  I 'm choosing to believe that you meant 7^(3x-1) and 5^(x-1).

Taking the common log of both sides, we get:

(3x-1)log 7 = (x-1)log 5

Then 3x·log 7 - log 7 = x log 5 - log 5

Grouping the x terms:

x(3·log 7 - log 5) = log 7 - log 5.  We combine log 7 and log 5, obtaining log (7/5).

Then x(3·log 7 - log 5) = log (7/5).

Solving for x:

      log (7/5)

x = ---------------------

      3·log 7 - log 5

        0.1461

x   = ------------- = 0.08

         1.0363

This agrees with the 3rd answer choice.

7 0
3 years ago
Please help me answer this question
MAXImum [283]

Step-by-step explanation:

BC is the bisector of \angle ABQ

\therefore \angle ABC \cong \angle CBQ..(1)\\\angle CBQ \cong \angle CAB..(2) \\(\angle 's\: in \: alternate\: segments) \\

From equations (1) & (2)

\angle ABC \cong \angle CAB\\\therefore AC = BC

(Because sides opposite to equal angles are equal)

Hence Proved

7 0
4 years ago
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