2 years ago

5TH GRADE LEVEL QUESTION: Look at photo and answer. handing out brainliest.

1 answer:

6 0

I agree there is no photo attached to the question.

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Ivahew [28]

Answer:

To know what the ratio for the cos of theta, we actually have to see the adjacent and hypotenuse values. cos=adjacent/hypotenuse.

Step-by-step explanation:

3 0

2 years ago

Yanka [14]

I=PRT
r=rat
P=present amount
I=interst
t=time in yeare

2 years
16%
3000
I=2*3000*0.16
I=$960

3 0

3 years ago

vitfil [10]

If the -8 is under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\$

If the -8 is not under the square root, then...

$\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5$

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

4 0

1 year ago

murzikaleks [220]

Answer:

dsynyerjtetuegrjghdgfs

6 0

3 years ago

natima [27]

For this, just plug in 1.5 into the x variable of this function and solve as such:

$f(1.5)=-16*1.5^2+112\\f(1.5)=-16*2.25+112\\f(1.5)=-36+112\\f(1.5)=76$

<u>The height of the object was at 76 ft.</u>

3 0

2 years ago