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2 years ago

5TH GRADE LEVEL QUESTION: Look at photo and answer. handing out brainliest.

Mathematics

1 answer:

Maksim231197 [3]2 years ago

6 0

I agree there is no photo attached to the question.

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What are the solutions to x2 + 8x + 7 = 0? A. x = –8 and x = –7 B. x = –7 and x = –1 C. x = 1 and x = 7 D. x = 7 and x = 8

NikAS [45]

Answer:

x= -7 x = -1

Step-by-step explanation:

x^2 + 8x + 7 = 0

Factor

What 2 numbers multiply to 7 and add to 8

7*1 = 7

7+1 = 8

(x+7)(x+1) =0

Using the zero product property

x+7 =0 x+1 = 0

x= -7 x = -1

8 0

2 years ago

Read 2 more answers

What is the answer to this 6+z/10 = -2 solve for z

PilotLPTM [1.2K]

6+z=10x-2
6+z=-20
Z=-20-6
Z=-26
Hope this helps!

7 0

2 years ago

PLEASE HELP THIS IS SUPER URGENT

vaieri [72.5K]

Answer:

have no idea lol im terrible at math

8 0

2 years ago

Kareem lives 4/10 of a mile from the mall. Write twp equivalent fractions that show what fraction of a mile Kareem lives from th

Vadim26 [7]

Answer:

Step-by-step explanation:

4/10 can be written in several different ways:

2/5, 40/100 (same as 0.4).

7 0

2 years ago

SOMEONE HELP ME ASAP PLZZ!!!

Black_prince [1.1K]

Answer:

The distance of the plane from the base of the tower is 25.5 foot.

Step-by-step explanation:

As given

Max is in a control tower at a small airport.

He is located 50 feet above the ground when he spots a small plane on the runway at an angle of depression of 27°.

Now by using the trigonometric identity.

$tan\theta = \frac{Perpendicular}{Base}$

As shown in the figure given below

Perpendicular = CB

Base = AC = 50 feet

$\theta = 27^{\circ}$

Put in the identity.

$tan\ 27^{\circ} = \frac{CB}{AC}$

$tan\ 27^{\circ} = \frac{CB}{50}$

$tan\ 27^{\circ} = 0.51\ (Approx)$

Put in the above

$0.51 = \frac{CB}{50}$

CB = 0.51 × 50

CB = 25.5 foot

Therefore the distance of the plane from the base of the tower is 25.5 foot.

4 0

2 years ago