Simplify the following expression. 24 + (3 × 5) - 4 - 9
2 answers:
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<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3
</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y
Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2
Divide that out and we get
</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y
Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2
Divide that out and we get
Answer:
Their mass at the start was 400 kg.
Step-by-step explanation:
Given:
The tyres on a car during a grand prix race are reduced in mass by 3%. Their mass is 388 kg at the end of the race.
Now, to find the mass at the start.
<u>Let the mass at the start be .</u>
According to question:
⇒
⇒
⇒
<em>Dividing both sides by 0.97 we get:</em>
⇒
Therefore, their mass at the start was 400 kg.