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Kay [80]
3 years ago
10

Determine the value of x. A. 5√3 B. 10√3 / 3 C. 10√3 D. 5

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

\huge\boxed{\sf B.}

Step-by-step explanation:

tan 30 = opposite / adjacent

<u>Where opposite = x , adjacent = 10 and tan 30 = √3 / 3</u>

\sf \frac{\sqrt{3} }{3} = \frac{x}{10} \\\\x = \frac{10\sqrt{3} }{3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

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A.5/12

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Solve 2x+y=7 for y what is y ?
masha68 [24]
You cant solve y but you can form an equation in terms of y
which is y=7-2x

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3 years ago
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Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.
Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

A=s^2 where s is the side length.

We know,  1 \text{ hectare}=10,000\ m^2

1) The area of square plot is 7 hectare.

Area in meter square is A=7\times 10000=70000\ m^2

Substitute the value in the formula,

70000=s^2

\sqrt{70000}=s

264.57=s

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is A=12\times 10000=120000\ m^2

Substitute the value in the formula,

120000=s^2

\sqrt{120000}=s

346.41=s

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is A=30\times 10000=300000\ m^2

Substitute the value in the formula,

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5 0
3 years ago
Solve the following word problems.
aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Let a , b , c & d be the no. of chairs in hall A , B , C & D respectively.

Given,

b = 4a

c = a + 15

d = a + 8 + 4a = 5a + 8

Now,

Total no. of chairs (T) = a + b + c + d

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Now,

Average chairs in each hall (Avg) = T/4

                                                       = (11a + 23)/4

7 0
3 years ago
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