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Vitek1552 [10]
2 years ago
9

What is the simplified value of the expression below?

Mathematics
2 answers:
bagirrra123 [75]2 years ago
7 0
1/2
Is the answer
To the problem
ankoles [38]2 years ago
7 0

Answer:

option C : 1/2

Step-by-step explanation:

\frac{1}{3} \div \frac{2}{3} \\\\\frac{\frac{1}{3}}{\frac{2}{3}}\\\\\frac{1}{3} \times \frac{3}{2} \\\\\frac{1}{2}

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Solve for c: <br> 12 - 9 + c = 12
enyata [817]

Step-by-step explanation:

12 - 9 + c = 12

-9 + c = 12 - 12

- 9 + c = 0

Therefore c = 9

Hope this helps.!

6 0
3 years ago
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What is the value of sin-1(1)? negative startfraction pi over 2 endfraction 0 startfraction pi over 2 endfraction π
mariarad [96]

The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

<h3>What is the value of sin (π/2)?</h3>

The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.

Suppose the value of this function is <em>x</em>. Thus,

x=\sin^{-1}(1)

Solve it further,

\sin(x)=(1)              ......1

The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1

Put this value in the equation 1,

\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)

Thus, the range will be,

\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

Learn more about the sine values here;

brainly.com/question/10711389

3 0
2 years ago
How do you find the lease common fatcor
8_murik_8 [283]

Answer:

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.


Step-by-step explanation:


4 0
3 years ago
Compare the two functions in the table. Will the value of function y = 2x eventually exceed the value of function y = x10?
Andrew [12]
First we rewrite the functions:
 y = 2x
 y = x ^ 10
We note that the second function always has values of y greater than the first function. However, there is a value of x for which the first function is greater.
 For x = 1 we have:
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 y = (1) ^ 10 = 1
 We note that:
 2> 1
 Answer: 
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3 years ago
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Whats the total volume of the cylinder
kondaur [170]
The answer is 88 Bc 8 x 11 is 88
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