Answer:
(7, -4.5)
Step-by-step explanation:
25−x=−4y ---> x=25+4y
3x−2y=30
use x to substitute into the second equation
3 (25+4y)-2y = 30
75+12y-2y=30
75+10y=30
10y=-45
y=-4.5
3x-2(-4.5)=30
3x+9=30
3x=21
x=7
check:
25-7=-4*-4.5
18=18 (yes)
3*7-2*-4.5=30
21+9=30
30=30 (yes)
Answer:
the total is $25 for a 5 mile ride.
the total is $40 for a 10 mile ride.
Step-by-step explanation:
x*3+y= total
5*3=$15
$15+$10=$25
10*3=$30
$30+$10=$40
Answer:
3 hours: 38,250
1 day: 122,440
I’m not sure if this is exactly right, my brain gave out half way. Someone check my answer pls
Step-by-step explanation:
3 hours: 3 x 60= 900
900 divided by 20= 450
450 x 85 = 38,250
1 day: 24 x 60 = 1440
1440 x 85 = 122,440
Answer:
(2,4) is a solution to this system of equations
Step-by-step explanation:
Given system of equation are


To find the solution of the given system of equations
To Check that (2,4) is a solution to this system or not
Solving equations (1) and (2)
From equation (1) and y=2x
Now substitute y=2x is equation (2)






10-5x=0
-5x=-10

Substitute x=2 in equation (1)
y=2x
y=2(2)
Therefore y=4
Therefore the solution is (2,4)
Therefore (2,4) is a solution to the system of equations.
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.