PLEASE HELP!

The next model of a sports car will cost 14.9% less than the current model. The current model costs $55,000. How much will the p

djverab [1.8K]

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<h3>Decrease In Price: </h3><h3>= 14.9% × $55,000 ÷ 100</h3><h3>= <u>$8,195</u></h3><h3 /><h3>Price Of Next Model: </h3><h3>= $55,000 - $8,195</h3><h3>= <u>$46,805</u></h3>

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8 0

3 years ago

Y=6x-11 -2x-3y=-7 solve each system of equation by substitution

Anit [1.1K]

Answer:

(2, 1 )

Step-by-step explanation:

Given the 2 equations

y = 6x - 11 → (1)

- 2x - 3y = - 7 → (2)

Substitute y = 6x - 11 into (2)

- 2x - 3(6x - 11) = - 7 ← distribute and simplify left side

- 2x - 18x + 33 = - 7

- 20x + 33 = - 7 ( subtract 33 from both sides )

- 20x = - 40 ( divide both sides by - 20 )

x = 2

Substitute x = 2 into (1) for corresponding value of y

y = 6(2) - 11 = 12 - 11 = 1

Solution is (2, 1 )

5 0

4 years ago

Leani makes a slice that results in a square. What slice did Leani make?

Thepotemich [5.8K]

A cut that is parallel to the base of the square based pyramid

7 0

4 years ago

Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba

Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let <em>X</em> = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.

The sample of items selected is of size, <em>n</em> = 150.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.

According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: $\mu_{\hat p}= p=0.05$

The standard deviation of this sampling distribution is: $\sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178$

If 10 of the 150 items produced are unacceptable then the probability of this event is:

$\hat p=\frac{10}{150}=0.067$

Compute the value of $P(\hat p\leq 0.067)$ as follows:

$P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315$

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0

3 years ago

Which statements correctly describe the association between the variables A and B?

postnew [5]

Answer:

positive association

linear association

Step-by-step explanation:

It is said that two variables A and B are related when the distribution of the values of one of the two variables differs according to the values of the other.

That is, when variable A grows then variable B also grows. This is known as positive correlation

When variable A grows then variable B decreases. This is known as negative correlation.

In the scatter plot you may notice that when variable A increases then variable B also increases, in an approximately linear relationship. Therefore it can be said that there is a positive and linear association.

The answer is the fourth and fifth option.

8 0

3 years ago