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3 years ago

Ill mark brainlist plss

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

6 0

Answer:

6/12

Step-by-step explanation:

the last one

4/8=6/12!!

Elan Coil [88]3 years ago

4 0

Answer:

4 : 8 = 6 : 12

Step-by-step explanation:

4 : 8 = 6 : 12

4 : 8 = 1 : 2

12 : 6 ≠ 1 : 2

10 : 12 ≠ 1 : 2

6 : 20 ≠ 1 : 2

6 : 12 = 1 : 2

4 : 8 = 6 : 12

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Slope intercept of (1,1) and (0,7)

Sonja [21]

Answer:

$\boxed {m = -6}$

Step-by-step explanation:

Use the Slope Formula to help you determine the slope of the following two points:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(Where $(x_{1}, y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Apply both points onto that formula:

$(x_{1}, y_{1}) = (1, 1)$

$(x_{2}, y_{2}) = (0, 7)$

$m = \frac{7 - 1}{0 - 1}$

-Solve:

$m = \frac{7 - 1}{0 - 1}$

$m = \frac{6}{-1}$

$\boxed {m = -6}$

3 0

3 years ago

Mum bought a litre of orange juice. She filled 4 glasses and had 1/2 litre left. How much was in each glass?

Bumek [7]

There was 1/8 liter of orange juice in each glass

3 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago

Jefferson Middle School needs to see a 300% gain in PTO fundraiser

Ronch [10]

Given parameters:

Percentage gain = 300%

Selling cost last year = $2420

Unknown:

Selling cost this year = ?

Solution:

To solve this problem;

Profit percent = $\frac{Selling cost this year - Selling cost last year}{Selling cost last year} x 100$

300 = $\frac{S - 2420}{2420} x 100$

3 = $\frac{S - 2420}{2420}$

S- 2420 = 7260

S = $9680

To make a 300% gain, Jefferson Middle school needs a $9680 from fundraiser sales this year.

6 0

3 years ago

Find the perimeter (add all sides) of a square when side a= - 41x²

Dafna11 [192]

Answer:

-164x^2

Step-by-step explanation:

The Perimeter of a square is 4s where s is the length of 1 side.

So P=4(-41x^2) 41*4=164 ----> P=-164x^2

5 0

3 years ago