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wel
3 years ago
14

IM DONE PLAYING AROUND NOW GUYS PLS HELP IM SERIOUS FJSKNSMS​

Mathematics
2 answers:
Kay [80]3 years ago
7 0

Answer: Mark me brainliest..

Step-by-step explanation: The answer will be in the comments if you do so. You've got nothing to lose! :D

Stella [2.4K]3 years ago
5 0

Answer:

im just here for the points Imao

Step-by-step explanation: always has been

You might be interested in
Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.
solniwko [45]

For this case we have to:

Letu = x + 1

So:

u ^ 2-4u + 2 = 0

We have the solution will be given by:

u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = 1\\b = -4\\c = 2

Substituting:

u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}

The solutions are:

u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}

Returning the change:

2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}

Answer:

x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}

3 0
3 years ago
Read 2 more answers
Find the midpoint of the segment with the following endpoints.<br> (-3,6) and (3,0)
Tresset [83]
Answer


(-3, 3)


Step-by-Step



-3-3/2=-6/2= -3
6-0/2= 6/2 = 3

(-3,3)
4 0
3 years ago
Inherently, industry analysis is a static framework, but it can be used in a quasi-dynamic way by applying the framework at diff
Liula [17]

Answer:

True

Step-by-step explanation:

Quasi-dynamic is a framework which accounts for inertial effects. In this we determine the long term behavior of state. It can be used to identify industry analysis where the industry is in a static state. Quasi static is a thermo-dynamic process that remains in internal equilibrium.

3 0
3 years ago
How many solutions does the system have?
amid [387]

Answer:

A; infinitely many solutions

Step-by-step explanation:

first, let's simplify the first equation to make it simpler.

divide both sides by 5

y=3x-8

new system

y=3x-8

y=3x-8

as you can see, they are the same.

not mandatory but useful!⬇⬇⬇⬇

just to be more clear, let's substitute them. since they're both already in y=, we can make them both set to each other.

3x-8=3x-8

add 8 to both sides; subtract 3x from one side

0=0

the answer is A, Infinitely many solutions.

hope this helped <3333333

8 0
3 years ago
There are 6 diagonals that can be drawn from one vertex of an octagon, true or false.
FinnZ [79.3K]
It's False; an octagon has 8 vertices. When you remove the starting vertex and the two adjacent vertices we're left with 5 possible diagonals
6 0
3 years ago
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