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3 years ago

What is the answer 9x plus 2 (2x+3)

Mathematics

2 answers:

avanturin [10]3 years ago

4 0

Answer :
13x+6

Step by step explanation:
9x+2 (2x+3)
= 9x + 4x + 6
= 13x + 6

alexandr402 [8]3 years ago

3 0

Step-by-step explanation:

=9x+2(2x+3)

=9x+4x+6

=13x+6 I hope so,

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Put a check by the three numbers that are prime numbers.<br> 1<br> 7<br> 15<br> 21

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Answer:

7 ✔️

Only 7 is a prime number in this question.

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3 years ago

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What would -9 1/2 be as a decimal?

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PLEASE LOOK AT THE IMAGE. I’m despite. It’s probably easy.

Sloan [31]

Answer:

Correct answer: (x - 10)² + y² = 441 / 4

Step-by-step explanation:

Given:

(a, b) = (10, 0) the coordinates of the center of the circle

(10, 21/2) circle passing through this point

The standard form of the circle equation is:

(x - a)² + (y - b)² = r² where r is radius of the circle

We will replace the given coordinates of the center of the circle and the point it passes through to get the radius of the circle:

(10 - 10)² + (21/2)² = r² ⇒ r² = (21/2)² = 441 / 4

r² = 441 / 4

(x - 10)² + y² = 441 / 4

God is with you!!!

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3 years ago

Mitchell is measured in February for the customs of a school play he’s 47 feet fabric he has 12 1/3 yards of fabric how many mor

Step2247 [10]

47- 12 1/3 = 34 2/3
He needs 34 and 2/3 feet more of fabric

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3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

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3 years ago