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3 years ago

Find the measure of the missing angles! Pls help thank you

Mathematics

1 answer:

Bond [772]3 years ago

3 0

Answer:

Step-by-step explanation:

d = 52°

e = 77°

f = 180° - ( 52° + 77° ) = 51°

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A square with side of k cm has perimeter of 36 cm. find the value of k.

Marrrta [24]

Answer: 9

Step-by-step explanation:

36/4 = 9

also if you want me to explain I can just ask…

but also I dunno if my answer is correct tho

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3 years ago

1. What is the marginal distribution of individuals who are underweight?

Katena32 [7]

Answer:

Step-by-step explanation:

You have to divide the TOTAL underweight which is 130, into the total of individuals which is 1000. 130/1000= 0.13 or 13.0%

Answer C.

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Answer:

Step-by-step explanation:

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2 years ago

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Minchanka [31]

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3 years ago

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Find the solution of the initial value problem dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

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3 years ago