Please please im beggin with my life help me

How many times does 9 go in to 8

Wittaler [7]

Answer:

0.89

Step-by-step explanation:

6 0

3 years ago

How do you do equations.

Nesterboy [21]

Do you have a specific equation I can help you with. I can explain them better with a problem to look at?

7 0

4 years ago

Read 2 more answers

Consider the graph of the function f(x)=(x−2)12 below. Which statements are true about the function f(x) ? Choose all that are c

Crazy boy [7]

The correct statements regarding the function in the graph are given as follows:

B. The function does not reach a maximum value.

C The function is increasing for all values of x larger than 2.

<h3>What are the correct statements regarding the function?</h3>

The function is defined for values of x or 2 and greater, and the function is increasing until infinity(hence it does not reach a maximum value) for all these values, hence statements B and C are correct.

More can be learned about functions at brainly.com/question/25537936

#SPJ1

5 0

2 years ago

What is the sum of two consecutive even integers divided by four is 189.5?

mixas84 [53]

Let us denote the smaller even integer by $N$ .
Then, the next even integer must be $N+2$ .

To verify, set $N$ as any even number, say $174$ .
Then, the next even integer must be 2 more than this number, i.e. $174+2=176$ .

The sum of these two consecutive even integers can be expressed as:
                                    $N+(N+2)=2N+2$

We are told that this sum divided by four is 189.5, i.e.
                                     $(2N+2)\div4=189.5$

Multiplying both sides by 4 will reverse the division:
     $(2N+2)\div4\times4=189.5\times4$
     $(2N+2)\times1=758$

Subtracting 2 from each side will reverse the addition:
     $2N+2-2=758-2$
     $2N=756$

Dividing both sides by 2 will reverse the multiplication:
     $2N\div2=756\div2$
     $N=378$

Therefore, the two consecutive integers must be 378 and 380.

Check this:
     $(378+380)\div4=758\div4=189.5$

3 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01

slavikrds [6]

Answer:

a) $z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

b) For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

$\hat p=\frac{174}{594}=0.293$ estimated proportion of yellow peas

$p_o=0.23$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:

Null hypothesis: $p=0.23$

Alternative hypothesis: $p \neq 0.23$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>3.649)=0.00026$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

5 0

3 years ago