Please please im beggin with my life help me

Jenny had 7 dimes and 3 pennies in her She takes a coin out from her pocket, looks at the coin and then replaces it her pocket b

alisha [4.7K]

<h3>Answer: 49/100</h3>

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Explanation:

There are 7 dimes and 3 pennies, leading to 7+3 = 10 coins total.

The probability of not picking a penny is 7/10. If the first coin is put back, then the probability doesn't change for the second selection.

The probability of getting two dimes is (7/10)*(7/10) = 49/100 when the first coin is replaced.

If the first coin is not replaced, then the answer would be (7/10)*(6/9) = 42/90 = 7/15

4 0

2 years ago

(Write your answers on the space provided) The World Health Organization (WHO) reported that about 16 million adolescent girls b

navik [9.2K]

The sequence of the number of girl attendees at each Barangay is nonzero, given by multiplying the number of attendees in the previous Barangay by 2

The required values are;

a. The completed table is presented as follows;

$\underline{\begin{array}{|l|c|c|c|c|c|c|c|}\mathbf{Barangay}&1&2&3&4&5&6&7\\\mathbf{Number \ of \ attandees}&4&8&16&32&64&128&256\end{array}}$

b. The sequence of the number of girls attendees aₙ = <u>4×2⁽ⁿ⁻¹⁾</u>

c. The sum of beneficiaries of the lecture from the twelve Barangay is <u>16,384 girls</u>

Reason:

Known parameters are;

Number of girls that attended the lecture at Barangay 1 = 4 girls

Number of girls that attended from Barangay 2 = 8 girls

Number that attended from Barangay 3 = 16 girls

a. The required table with the assumption that the number of girls that attended at each Barangay from Barangay 1 to Barangay 7 doubles, is presented as follows;