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adelina 88 [10]
3 years ago
12

If the area of a square is 7.29 square yards, what is the length of one of the sides?

Mathematics
1 answer:
In-s [12.5K]3 years ago
7 0

Answer:

2.7

Step-by-step explanation:

Since the shape is a square, just square root its area to get its side's sides.

Square root 7.29:

2^2 is 4, and 3^2 is 9, so we know that the answer is somewhere between 2 and 3

Let's try 2.5:

2.5^2 = 2.5*2.5 = 6.25, not quite

Let's try 2.6:

2.6^2 = 2.6*2.6 = 6.76, still a bit short

Let's try 2.7:

2.7^2 = 2.7*2.7 = 7.29, We have 7.29, so 2.7 is the answer!

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0 & 1

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3(1 + x) < x + 6

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3 years ago
Cuboid ABCDEFGH is shown
gtnhenbr [62]

Answer:

The angle formed between CF and the plane ABCD is approximately 47.14°

Step-by-step explanation:

The given parameters are;

BC = 6.8

DE = 9.3

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We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;

sin∠BAC = BC/(The length of a line drawn from A to C)

∴ The length of the line drawn from A to C = BC/sin∠BAC

The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63

∴ AC = 8.63

By trigonometry, we have;

The angle formed between CF and the plane ABCD = Angle ∠ACF

tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length}

tan\angle ACF = \dfrac{FA}{AC}

In a cuboid, FA = BG = CH = DE = 9.3

\therefore tan\angle ACF = \dfrac{9.3}{8.63}

\therefore \angle ACF = arctan \left(\dfrac{9.3}{8.63} \right) \approx 47.14^{\circ}

The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°

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3 years ago
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