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KiRa [710]
3 years ago
5

The volume of a cylinder is 32.25 cubic inches. If a cone has the same height and radius as the cylinder, what is its volume?

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

The volume of a cylinder with a radius r and a height h:

V_1=\pi r^2h

The volume of a cone with a radius r and a height h:

V_2=\dfrac{1}{3}\pi r^2h

Therefore

V_2=\dfrac{1}{3}V_1

We have V_1=32.25\ in^3

Substitute:

V_2=\dfrac{1}{3}\cdot32.25=10.75\ in^3

Answer: The volume of a cone is equal 10.75 in³

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The equation y = kx represents a proportional relationship between x and y, where k is the constant of proportionality. For a mo
valentinak56 [21]

Answer:

Step-by-step explanation:

y = kx represents a proportional relationship between x and y

where,

k is the constant of proportionality

Given:

d = st

Where,

d = distance

s = speed

t = time

The constant of proportionality of the quantities d, s and t is speed(s)

Speed(s) remains constant at a given time and distance

The equation can be written in different forms below:

d = st

S = d/t

t = d/s

Real world example of proportional relationships

• F=ma

Where,

F=Force

m=mass

a=acceleration

F=ma is used to calculate force

3 0
3 years ago
2/3 of 16 <br><br><br><br><br><br> ...........................
maxonik [38]

Answer:

2/3 * 16

32/3 = 10.66

hope it helps

5 0
3 years ago
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The sum of a number x and 5 equals 14
pav-90 [236]

Answer:

x=9

Step-by-step explanation:

Since x+5=14, then you would subtract 5 from 14. 14-5=9. So that means x equals 9.

3 0
4 years ago
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If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!
timama [110]

x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0

By the quadratic formula,

x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2

Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

3 0
3 years ago
Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,
olganol [36]

ANSWER

No solution

EXPLANATION

The first equation is

y =  {x}^{2}  - 2x

and the second equation is

y =  - 2x  - 1

We equate the two equations to obtain;

{x}^{2}  - 2x =  - 2x - 1

This implies that

{x}^{2}  =  - 2x + 2x - 1

{x}^{2}  =  - 1

There is no real number whose square is -1.

Therefore, the equation has no solution.

6 0
3 years ago
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