Answer:
sq root of 6 divided by 2
Step-by-step explanation:
use pythagorean theorem: square of each leg equals the square of the hypotenuse
x squared plus x squared = radical three squared
2x² = 3
x² = 
x = square root of 3/2
rationalize the denominator to get sq root of 6 divided by 2
The values of the variables are k = -6 , w = ± 9 , f = -7
Step-by-step explanation:
To solve these problems we will compare the elements inside the [ ]
[-12 , -w²] = [2k , -81]
[2f , 3] = [-14 , 3]
That mean:
1. -12 = 2k
2. -w² = -81
3. 2f = -14
∵ 2k = -12
Divide both sides by 2 to find k
∴ k = -6
∵ -w² = -81
Divide both sides by -1
∴ w² = 81
Take √ for both sides
∴ w = ± 9
∵ 2f = -14
Divide bith sides by 2
∴ f = -7
The values of the variables are k = -6 , w = ± 9 , f = -7
Learn more:
You can learn more about simple equation in brainly.com/question/13113987
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(-8)x=(-6)x+10
(-2)x=10
X=10/-2
X=-5
230 X .82 = 188.6
188.6 is the answer
