What is the approximate radius of a sphere with a volume of 268 cm^3?

Mathematics

1 answer:

pav-90 [236]3 years ago

5 0

Answer:

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3~=>r=\sqrt[3]{\frac{3V}{4\pi}}=\sqrt[3]{\frac{3*260cm^3}{4\pi}}=3.96 \approx4$

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How to solve all of this

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Move diagonally to the circle with the radius of 6.2.

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Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

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Move down to the circle with the diameter of 50

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Move left to the circle with the radius of 11.8

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Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

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Move right to the circle with the radius of 14.8

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