<u>answer (in words)</u>
FALSE. the coordinate pair (5, 2) is not a solution to the equation 
. in order to figure out whether or not the statement is true or false, plug the 
and 
values from the coordinate pair (5, 2) into the given equation, . if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.
<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>
<u>answer (algebraic/steps for solving)</u>
first, plug in 5 for in the equation .
- ⇒
then plug in 2 for .
- ⇒
now your equation is . all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.
- ⇒
multiply 3 · 2.
- ⇒
add 10 + 6.
- ⇒
16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation . in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.
i hope this helps! have a great rest of your day <3
Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
What were your given answer choices
Here is you answer , happy today
Answer:
y-3 = -12 (x-5)
Step-by-step explanation:
The point slope form of an equation is
y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point
y-3 = -12 (x-5)
