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castortr0y [4]
3 years ago
6

3. Farmer Brown is growing crops. In his field he has 25 square fe of corn and 25 square feet of wheat. What is the area of Farm

er Brown's field?​
Mathematics
2 answers:
Romashka [77]3 years ago
7 0

Answer:

50 square feet

Step-by-step explanation:

If he has 25 square feet in corn and 25 in wheat so add them together and you get the full area of the entire field

skad [1K]3 years ago
3 0

Answer:

25 x 25= you gey ur answer

Step-by-step explanation:

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A jacket is on sale for 20% off the regular price. The sale price ism$50.00. What is the regular price of the jacket?
Delicious77 [7]
Lets solve for x.

 0.8x = 50. - Remember that the jacket was 80% of the original price.

Thus, divide by x.

x = 50 / 0.8
x = 62.5
7 0
3 years ago
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PLSSS HELP!!! 40 pts!!!!
quester [9]

Answer:

∠1=135°

∠2=45°

∠3=45°

∠4=135°

∠5=135°

∠6=45°

∠7=45°

∠8=135°

Step-by-step explanation:

→∠1=∠4[Being vertically opposite angles]

→∠4=135°

→∠1=∠5[Corresponding angles]

→∠5=135°

→∠5=∠8[Being vertically opposite angles]

→∠8=135°

→∠1+∠2=180°[Sum of linear pair]

→∠2=180°-135°

→∠2=45°

→∠2=∠3[Being vertically opposite angles]

→∠3=45°

→∠3=∠6[Alternate angles]

→∠6=45°

→∠6=∠7[Being vertically opposite angles]

→∠7=45°

3 0
2 years ago
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M\-9&lt;10<br><br> please at least try:)
ASHA 777 [7]

m=90

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7 0
3 years ago
An extended recessionary period is indicative of
exis [7]

Answer:

D) the end of a recession.

Step-by-step explanation:

During the recession period, the unemployment rate is high which is indicative of depression and people suffer from financial crises and gross domestic product ...

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I'll. ark brainlyest and give a lot of points for answering this right ​
valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

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