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Finger [1]
3 years ago
15

Find the shaded area of the figure. Please help I am giving brainliest

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0

Answer:   25pi/3  square units

=============================================================

Explanation:

If that point is the center, then we have two pizza slices that sweep out 60 degrees of a central angle.

The full circle has pi*r^2 = pi*5^2 = 25pi square units of area

We only want 60/360 = 1/6 of that for each slice, so 2*(1/6) = 1/3 of the full circle area is shown by the shaded region

(1/3)*(full circle area) = (1/3)*25pi = 25pi/3  square units is the shaded area

Varvara68 [4.7K]3 years ago
7 0

Answer:

do u mean the degree? if u do then it would be 60

Step-by-step explanation:

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14-(x+5)=3(x+9)-10 please help quick and show work!
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Answer:

x=-2

Step-by-step explanation:

14-(x+5)=3(x+9)-10

14-x-5=3x+27-10

14-5-x=3x+17

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9=4x+17

-17    -17

4x=-8

4x/4=-8/4

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1,800,000 - 3% =

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1,800,000 - 1,746,000 =

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2 years ago
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4 0
2 years ago
Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
3 years ago
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