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3 years ago

If the center of a circle is (1,1) and it has a radius of 5, which is another point on the circle

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

6 0

Check the picture below.

dezoksy [38]3 years ago

4 0

The answer is (4,5).

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"If a = − 9 and b = − 6, show that (a−b) ≠ (b−a)."

denis-greek [22]

Answer:

Step-by-step explanation:

LHS a - b = -9 - (-6) = -9 +6 = -3

RHS b-a = -6 - (- 9) = -6 +9 = 3

as LHS not equal to RHS

a-b not equal to b-a

Thus proven

7 0

3 years ago

F(x)=3x+2 and g(x)=-2x-4, find h(x) = f(x)-g(x)

elena-14-01-66 [18.8K]

Answer:

5x-2

Step-by-step explanation:

Since f(x)-g(x) you take 3x+2 and subtract -2x-4.

3x+2+2x-4

5x-2

6 0

3 years ago

If i have 38 assignments and i do 15 of them what percentage do i have done?

netineya [11]

Answer:

39.473%

Step-by-step explanation:

It is actually fairly simple to get the answer to this. What you can do to find any percentage, is to take the amount done, or whatever it is in the scenario, and divide it by the total. It is like turning it into a fraction, which you can do as well. Turn this into a fraction, and then convert it. 15/38, 15 divided by 38 = 39.473.

Hope this helped ^-^

4 0

3 years ago

Read 2 more answers

The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?

BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
$A_{n}=A_{1}+(n-1)d$

$A_{n}$ is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so $A_{1}=47$
d=-2 because the question gives you that

$A_{n}=A_{1}+(n-1)d$
 $A_{29}=47+(29-1)(-2)$
 $A_{29}=47+(28)(-2)$
 $A_{29}=47+-56$
 $A_{29}=-9$

The answer is A. -9.

 

The answer is C. 158

For the second one, it gives you $A_{1}=4$ and $A_{}=18$
You can use this to find d

 $A_{n}=A_{1}+(n-1)d$
 $A_{3}=4+(3-1)d$
 $18=4+(3-1)d$
 $18=4+2d$
 $14=2d$
 $7=d$

Now you can just solve using the equation normally.
 $A_{n}=A_{1}+(n-1)d$
 $A_{23}=4+(23-1)(7)$
 $A_{23}=4+(22)(7)$
 $A_{23}=4+154$
 $A_{23}=158$

The answer is C. 158

8 0

3 years ago

Read 2 more answers

.....help me please

Virty [35]

Your answer would be A

3 0

3 years ago