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2 years ago

The Ages of mark and Adam add up to 28 years total mark is 20 years older than Adam how old is adam

Mathematics

1 answer:

aleksandrvk [35]2 years ago

6 0

Answer:

Adam is 8.

Step-by-step explanation:

28-20=8

Can I get brainliest? Working on next rank.

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Tim's bank contains quarters, dimes and nickels. He has 3 more dimes than quarters and 6 fewer nickels than quarters. If he has

Aleksandr-060686 [28]

(x - 3) + (x - 6) + x = 63
x - 3 + x - 6 + x = 63
Combine like terms
3x - 9 = 63
Isolate the constant
3x - 9 + 9 = 63 + 9
3x = 72
Isolate the viable
3x / 3 = 72 / 3
x = 24

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4 0

3 years ago

Write an equation in slope-intercept form of the line with the parametric equations x=2t and y=1-t

pentagon [3]

Answer: -x/2 + 1

Step-by-step explanation:

write t in terms of x

x = 2t

t = x/2

substitute t in y

y = 1 - t

y = 1 - x/2 or -x/2 + 1

6 0

3 years ago

Read 2 more answers

-5(w+4) +8< - 42 need a quick answer

Nesterboy [21]

Answer:

$w > 6$

Step-by-step explanation:

Let's solve your inequality step-by-step.

−5(w+4)+8<−42

Step 1: Simplify both sides of the inequality.

−5w−12<−42

Step 2: Add 12 to both sides.

−5w−12+12<−42+12

−5w<−30

Step 3: Divide both sides by -5.

$\frac{-5w}{-5} < \frac{-30}{-5}$

$w > 6$

<u>Answer: </u>

<u /> $w > 6$

Thanks!

- Eddie

7 0

1 year ago

The number 18 is what % of 56?

zalisa [80]

X
--- × 56 =18
100

56x = 18×100

× = 18 × 100
- - - - - - -
56

X = 32.14%

7 0

3 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

7 0

2 years ago