The average (arithmetic mean) of 0, a, and b is 2a. What is the value of b in terms of a?

I need help ASAP -2x^2+x 9-25x^2+8x X^5+x^3-x^2-1

nika2105 [10]

Answer:

For $-2x^2+x$ , Leading coefficient is -2, Degree is 2, Constant term is 0

For $9-25x^2+8x$ , Leading coefficient is -25, Degree is 2, Constant term is 9

For $x^5+x^3-x^2-1$ , Leading coefficient is 1, Degree is 5, Constant term is -1

Step-by-step explanation:

Given:

Polynomials:

$-2x^2+x\\9-25x^2+8x\\x^5+x^3-x^2-1$

To find: leading coefficient, constant term and degree

Solution:

Leading coefficient is the coefficient of the variable with the highest power.

Degree is the highest power of the variable.

The term of degree 0 is the constant term of a polynomial.

For $-2x^2+x$ ,

Leading coefficient is -2

Degree is 2

Constant term is 0

For $9-25x^2+8x$

Leading coefficient is -25

Degree is 2

Constant term is 9

For $x^5+x^3-x^2-1$

Leading coefficient is 1

Degree is 5

Constant term is -1

4 0

4 years ago

Alice and her two sisters, Betty and Carol, are avid tennis players. Betty is the best of the three sisters, and Carol plays at

jeka94

Answer:

0.484

Step-by-step explanation:

Given that:

Alice defeats Carol 50% of the time.

This implies that, the probability of defeating Carol = 0.5

Also the probability of losing to Carol = 1 - 0.5 = 0.5

Similarly, Alice defeats Betty 40% of the time.

The probability of Alice defeating Betty = 0.4 and the probability of losing to Betty = 1 - 0.4 = 0.6

However, in as much as Alice needs to win two consecutive games, the sequence which satisfies this condition are as follows:

Let W represent Win and L represent L.

Then the conditions are WWW, WWL and LWW

Since the outcome of each game is independent of the other games.

Then, the probability that Alice wins two games against Carol CBC is:

Pr(2W - CBC) = (0.5 × 0.4 × 0.5) + ( 0.5 × 0.4 × 0.5) + ( 0.5 × 0.4 × 0.5)

Pr(2W - CBC) = 0.1 + 0.1 + 0.1

Pr(2W - CBC) = 0.3

The probability that Alice wins two games against Betty (BCB) is:

Pr(2W - BCB) = (0.4 × 0.5 × 0.4) + (0.6 × 0.5 × 0.4) + ( 0.4 × 0.5 × 0.6)

Pr(2W - BCB) = 0.08 + 0.12 + 0.12

Pr(2W - BCB) = 0.32

However, the Probability of winning two consecutive games is the result of the addition of the probability of winning two consecutive games in the sequence CBC together with the probability of winning two consecutive games in the sequence of BCB.

i.e.

Pr(2W) = Pr(2W- CBC) + Pr(2W - BCB)

Pr(2W) = 0.3+0.32

Pr(2W) = 0.62

Finally, to calculate the probability that Alice will get $100 if she chooses the sequence CBC is:

$\dfrac{Pr(2W -CBC)}{Pr(2W)}= \dfrac{0.3}{0.62}$

$\mathbf{\dfrac{Pr(2W -CBC)}{Pr(2W)}= 0.484}$

7 0

3 years ago

What is the perimeter of a square abcd if a(0,0 and b(0,5?

Ghella [55]

So squares have 4 congruent sides. When you plot the points (0,0) and (0,5) the side length is 5 units. We can then take 5+5+5+5 and know the perimeter is 20 units.

4 0

3 years ago

Read 2 more answers

Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x = cos(θ) + sin(10

vivado [14]

Answer:

Step-by-step explanation:

x = cos θ + sin(10θ)

y = sin θ + cos(10θ)

Take derivative with respect to θ:

dx/dθ = -sin θ + 10 cos(10θ)

dy/dθ = cos θ - 10 sin(10θ)

Divide:

dy/dx = (dy/dθ) / (dx/dθ)

dy/dx = (cos θ - 10 sin(10θ)) / (-sin θ + 10 cos(10θ))

Evaluate the derivative at θ=0:

dy/dx = (cos 0 - 10 sin 0) / (-sin 0 + 10 cos 0)

dy/dx = 1/10

Evaluate the parametric functions at θ=0:

x = cos 0 + sin 0 = 1

y = sin 0 + cos 0 = 1

Writing the equation of the tangent line in point-slope form:

y - 1 = 1/10 (x - 1)

6 0

3 years ago

What is 0.49,0.5 and 1/5 from least to greatest?

brilliants [131]

1/5 (0.2)
0.49
0.5

Hope this helped!! xx

7 0

3 years ago