Answer:
Step-by-step explanation:
Given that
To find tangent, normal and binormal vectors at (0,0,1)
i) Tangent vector
At the particular point, r'(t) = (1,1,e)
Tangent vector =
ii) Normal vector
T'(t) =
At that point T'(t) = (0,0,e)/e = (0,0,1)
iii) Binormal
B(t) = TX N
=
Answer:
Step-by-step explanation:
No it doesn't. When you get stuck on a question like this one, you should go to Desmos and graph the equation. I've done that for you.
Correctly stated the equation should read f(x) = (x + 2)^2 + 4
As you can see from the graph the vertex is at -2,4. To find the x value of the vertex, create a small equation
x + 2 = 0
x = - 2
That will turn what is inside the brackets into 0. The value for x is always what will turn (x + a) to zero.
