The approximation of which irrational number is shown by point R on the number line?
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The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
<h3>Absolute values of the complex numbers</h3>The absolute values of the complex numbers are determined as follows;
(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴
(-1+sqrt3i)^12 = (-1 + √3i)¹²
(sqrt 3-i)^6 = (√3 - i)⁶
(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸
(sqrt2-i)^6 = (√2 - i)⁶
Increasing order of the complex numbers;
(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.
Learn more about complex numbers here: brainly.com/question/10662770
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To find which of the following roots is between "8" and "7" we can calculate the root of which numbers result in 8 and 7. To do this we will power them by 2, this is done because power is the oposite operation to the root. Doing this gives us:
So the root of 64 is 8 and the root of 49 is 7. We need to find the number that is between 49 and 64.
From the options the only one that qualifies is 52. The correct option is b.