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natka813 [3]
3 years ago
12

The voting trends for 163 countries were studied. Malta was rated number 1, but was left off of Table 2-2 which is a random samp

ling from a larger table.. . . Based on the information that is included in Table 2-2, what can you say about the percent that voted in Malta?. .
Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0
I think the possible way that the percentage vote of a country is different to the next random sampling to the other data table is its population in each country. In the first table i think Malta has the edge to this table data and place in number 1 but to the other data table the country was left of. 
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Jelly ate 3 apples. This represents 50% of the bag of apples. How many apples were originally in the bag
rjkz [21]
<h3>Answer:  6 apples</h3>

x = number of apples originally

50% of x = 0.50*x = amount of apples eaten = 3

0.50x = 3

x = 3/0.50 ....... divide both sides by 0.50

x = 6

You can think of 50% as 1/2. If 3 apples represent half the bag, then the full bag is 6 apples. So half of 6 is 3.

6 0
2 years ago
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1,3,2,6,3,9,4,12... what will be the eleventh number in the pattern?
katrin [286]

Answer:

11th number is 6

Step-by-step explanation:

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1 year ago
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The number 12,089 is?
Ratling [72]
12,089 is less than 12,098
The first choice is the correct one.
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3 years ago
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
Lucy will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $53 and costs an add
Alchen [17]

Answer:

The amount driven would be 275, and the cost for both plans will be 77.75$

Step-by-step explanation:

make both equations

y=0.09x+53

y=0.13x+42

set them equal to each other and solve for x to get the distance

take that number and put it in one equation and solve for y to get the price of the plan for that value

6 0
2 years ago
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