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shusha [124]
2 years ago
15

Which table shows a proportional relationship

Mathematics
1 answer:
yarga [219]2 years ago
5 0

<h3>stop using this website just for answers, it's cheating, and it doesn't help you learn anything. Instead, you SHOULD ask how to figure out the question you're asking.</h3><h3>For example: how do I figure out which table represents a proportional relationship?</h3>

answer: look for a common Multiple

The answer is option two, "S" represents one and "R" represents five

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The rate of change is -1
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A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (6, 5). What is
OLga [1]

Answer:

The vector joining the ship to the rock is t= 7 i + 5 j

The direction is 0.9505 radians east of north.

Step-by-step explanation:

The position vector of the ship:

r= 1 i + 0 j

The position vector of the ship:

s= 6 i + 5 j

The vector joining the ship to the rock is:

t = r + s

t = (1 i + 0 j) + (6 i + 5 j)

t = 7 i + 5 j

The bearing of the rock to the ship is:

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What is an easy method to workout 35% of 70
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Step-by-step explanation:

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If 4x+3x-2(x+5)=-9 then x=?
Nana76 [90]

Answer:

X=1/5

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g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
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Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

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The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
3 years ago
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