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3 years ago

Which table shows a proportional relationship

Mathematics

1 answer:

yarga [219]3 years ago

5 0

<h3>stop using this website just for answers, it's cheating, and it doesn't help you learn anything. Instead, you SHOULD ask how to figure out the question you're asking.</h3><h3>For example: how do I figure out which table represents a proportional relationship?</h3>

answer: look for a common Multiple

The answer is option two, "S" represents one and "R" represents five

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Will give brainliest answer. If explained..

Stolb23 [73]

It C. and if you need the equation for the area of a parallelogram its A=BH

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4 years ago

One-half of the sum of a number and 6 is less than 25. What is the number

Leno4ka [110]

Answer:

Step-by-step explanation:

1/2(n + 6) < 25 Distribute

1/2n + 3 < 25

- 3 - 3 Subtract 3 from both sides

1/2n < 22 Multiply both sides by 2 or divide by 1/2

n < 44

If this answer is correct, please make me Brainliest!

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4 years ago

Please help and show work i need it asap

Veseljchak [2.6K]

Answer:
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Please see the picture attached!

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3 years ago

Read 2 more answers

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3 years ago

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

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4 years ago