Question

Y <= - 1/3 * x + 2; y > 2x - 3 linear inequalities

Answer 1

Step-by-step explanation:

Given

Inequalities are $y\leq -\dfrac{1}{3}x+2$ and $y>2x-3$

Take the inequality as two equations to get the intersection point

$y=-\dfrac{1}{3}x+2\ and\ y=2x-3$

Equate the value of y

$\Rightarrow -\dfrac{1}{3}x+2=2x-3\\\Rightarrow 5=\dfrac{7x}{3}\\\\\Rightarrow x=\dfrac{15}{7}$

$\therefore y=1.286$

The common region gives the required regions for inequalities.