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S_A_V [24]
3 years ago
14

Which of these describes a quantitative observation?

Biology
1 answer:
Sergio [31]3 years ago
3 0

Answer: <u><em>D. An observation that has a number associated with it</em></u>

Explanation: The answer is D. An observation that has a number associated with it. I would explain further, but it is pretty self explanatory.

<em>Good luck!</em>

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Three kinds of waste that the body will get rid of through the excretory system
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gas, liquid & a solid

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A locus that affects susceptibility to a degenerative brain disease has two alleles, V and v. In a population, 16 people have ge
Pie

Answer:

Yes, the population is evolving

Explanation:

Hardy-Weinberg equilibrium states that a population is not evolving if it is in hardy weinberg equilibrium as the alleles frequency do not change over time in generations.

In mathematical equation, the genotype frequency will be -P²+2Pq+q²=1 and allele frequency will be p+q=1, where p = dominant allele and q will be recessive allele.

In the question, since the observed genotype are-

P² - VV= 16

2Pq- Vv- 92

q²- vv- 12

<u>1. Calculate allele frequency</u>

Now we will calculate if the expected value is same or close or not.

We will calculate allele frequency

Population has 120 individuals which means it has - 240 alleles.

In which V (p) will be- 32 +92= 124 allele

p- dominant allele/ total allele=  124/ 240 = 0.52

P= 0.52

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<u>2. Expected genotype frequency</u>

Now we will calculate expected genotypic frequency.

P²- 0.52 X 0.52= 0.27

2Pq = 2 x 0.52x 0.48 =  0.5

q²= 0.48 x 0.48 =  0.23

<u>3. Expected progeny </u>

P²= 0.27 x 120= 32 VV

2Pq= 0.5 X 120= 60 Vv

q²= 0.23 x 120= 28 vv

Since the observed value is not equal to the expected value therefore the population is not in Hardy- Weinberg equilibrium and the population is evolving.

Thus, Yes, the population is evolving is correct.

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In Mendel's pea plants, tall(T) is dominant to short (t), white(W) flowers are dominant to purple
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Answer:

Tt x Tt  =  1 TT : 2 Tt : 1 tt

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T        TT       Tt

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