Find four consecutive integers such that the sum of the third and forth is 37
1 answer:
Answer:
16 17 18 19
Step-by-step explanation:
x+(x+1)+(x+2)+(x+3)
3rd and 4th: (x+2)(x+3) = 2x+5
2x+5 = 37
2x = 32
x=16
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