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Digiron [165]
3 years ago
7

Find four consecutive integers such that the sum of the third and forth is 37

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

16 17 18 19

Step-by-step explanation:

x+(x+1)+(x+2)+(x+3)

3rd and 4th: (x+2)(x+3) = 2x+5

2x+5 = 37

2x = 32

x=16

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Need help, show work on a piece of paper<br>on problem 8
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<h3>Given</h3>
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<h3>Find</h3>
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<h3>Solution</h3>

Substituting the given values of the angles into the given relaion, we get ...

... (x² -2) + (2x -10) + (x² -2) = 16x +2

... 2x^2 -14x -16 = 0 . . . . . subtract the right side (16x+2)

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... ∠BOC = 2·8 -10 = 6

... ∠AOD = 16·8 +2 = 130 . . . . = 62 +6 +62

The answer to the question not asked is ...

... x = 8; ∠AOB = ∠COD = 62; ∠BOC = 6; ∠AOD = 130

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OlgaM077 [116]

Answer:

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Step-by-step explanation:

I think the answer choices were supposed to be:

\sqrt{3} , \sqrt{6} , \sqrt{39} , \sqrt{89}

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