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Paul [167]
3 years ago
8

What are the zeros of the polynomial below (x + 3)(x - 5) =0

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0

Answer:

-3, 5

Step-by-step explanation:

By solving for x you get -3 and 5.

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Stolb23 [73]

According to the system:

5 – 7x + 2y² = -10

1 – 5x – 2y = -22

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a) No ; (4, 6) is not a solution to the

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b) No ; (6, 4) is not a solution to the system. This point does not touch either equation.

Solutions:

( \frac{122 - 3 \sqrt{101}}{25}, \frac{ - 7 +3 \sqrt{101}}{10}) ≈ (3.674, 2.315) \\ ( \frac{122  +  3 \sqrt{101}}{25}, \frac{ - 7  - 3 \sqrt{101}}{10}) ≈ (6.086, -3.715)

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3 years ago
Combine the following sets of terms.
DanielleElmas [232]

Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

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Combine Like Terms:)

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Answer :)

=2x2−10x+9


HOPE THIS HELPS

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