Does anyone know how to do this?
2 answers:
Answer:
√45
Step-by-step explanation:
We know that according to the Pythagorean theory:
a²+b²=c²
I am pretty sure that a is 3 and b is 6. C remains unknown.
3 squared is nine and 6 squared is thirty six. 36+9 is 45.
Since the question says you should leave the answer in radical form, the answer is
c²=45
√c²=√45
This book will really help in Geometry and you can get it anywhere.
I hope this helps!
~°LampteyJ
For this you would need to use the Pythagorean theorem! a^2 + b^2 = c^2
So if a=3 and b=6 then c=?(hypotenuse)
(3x3) + (6x6) = c^2
9 + 36 = c^2
45 = c^2
To get “c” by itself you need to take the square root of both sides of your equation which will eliminate the square on the side with “c”
Square root of 45 = (in radical form)
3 x square root of 5
So if a=3 and b=6 then c=?(hypotenuse)
(3x3) + (6x6) = c^2
9 + 36 = c^2
45 = c^2
To get “c” by itself you need to take the square root of both sides of your equation which will eliminate the square on the side with “c”
Square root of 45 = (in radical form)
3 x square root of 5
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Answer:
0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Probability of a person being in May:
May has 31 days in a year of 365. So
Group of 20 friends:
This means that
What is the probability that at the May celebration, exactly two members of the group have May birthdays?
This is P(X = 2).
0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays