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2 years ago

6

Does anyone know how to do this?

2 answers:

mr_godi [17]2 years ago

8 0

Answer:

√45

Step-by-step explanation:

We know that according to the Pythagorean theory:

a²+b²=c²

I am pretty sure that a is 3 and b is 6. C remains unknown.

3 squared is nine and 6 squared is thirty six. 36+9 is 45.

Since the question says you should leave the answer in radical form, the answer is

c²=45

√c²=√45

This book will really help in Geometry and you can get it anywhere.

I hope this helps!

~°LampteyJ

Natalka [10]2 years ago

8 0

For this you would need to use the Pythagorean theorem! a^2 + b^2 = c^2
So if a=3 and b=6 then c=?(hypotenuse)

(3x3) + (6x6) = c^2
9 + 36 = c^2
45 = c^2

To get “c” by itself you need to take the square root of both sides of your equation which will eliminate the square on the side with “c”

Square root of 45 = (in radical form)
3 x square root of 5

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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

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From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

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$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

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∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

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After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

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At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

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$58 = -20+106 e^{k(1)}$

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$ln(e^{k}) =ln( 0.735849)$

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This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

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Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

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