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bagirrra123 [75]

3 years ago

14

let's say we did flip the coin 200 times, it landed on heads all 200 times what is the probability that the coin would land on h

eads if we flip it one more time

1 answer:

AnnZ [28]3 years ago

8 0

50/50 bc even tho it may land on heads there is still two sides (50/50) that may end in tails hope I helped

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Suppose a three-seat city council election. For each seat, one progressive and one conservative is running, and voters must choo

Kitty [74]

Answer:

The probability that conservative party wins all 3 seats is 0.216

The probability that conservative party wins exactly two seats is 0.432

Step-by-step explanation:

Consider the provided information.

The probability of a conservative candidate winning is p=0.6.

The probability of one progressive candidate will win is: 1-0.6=0.4

Part (a) What is the probability that the conservative party wins all three seats?

According to binomial distribution: $b(x; n, p) =^nC_xp^x(1- p)^{n-x}$

$P(x=3) =^3C_3(0.6)^3 (0.4)^{3-3}$

$P(x=3) =(0.6)^3$

$P(x=3)=0.216$

P(conservative party wins all 3 seats) = 0.216

Hence, the probability that conservative party wins all 3 seats is 0.216

Part (a) What is the probability that the conservative party wins exactly two seats?

$P(x=2) =^3C_2(0.6)^2 (0.4)^{3-2}$

$P(x=2) =3(0.36)(0.4)$

$P(x=2) =0.432$

Hence, the probability that conservative party wins exactly two seats is 0.432

5 0

3 years ago

Use the counting techniques from the last chapter. A bag contains three red marbles, four green ones, one fluorescent pink one,

sergiy2304 [10]

Answer:

The probability that she gets all the red ones, given that she gets the fluorescent pink one, is P=0.0035 or 0.35%.

Step-by-step explanation:

Susan grabs four marbles at random.

We have to calculate the probabilities that he picks the 3 red ones, given that she already picked the fluorescent pink.

If it is given that the fluorescent pink is already picked, we are left with three red marbles, four green ones, two yellow ones, and four orange ones. A total of 13 marbles.

The probability that the second marble is red is 3 in 13.

The probability that the third marble is also red is 2 (the red marbles that are left) in 12 (the total amount of marbles left), as there is a picking without replacement.

The probability that the fourth marble is 1 in 11.

Then, the probability that the 3 red marbles are picked, is:

$P=P_1\cdot P_2\cdot P_3=\dfrac{3}{13}\cdot \dfrac{2}{12}\cdot \dfrac{1}{11}=\dfrac{6}{1716}=0.0035$

4 0

3 years ago

Simplify x0 y-3/x2 y-1

Natali5045456 [20]

Answer:

x^0 y^-3 / x^2 y^-1

= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2

= 1/(x^2 y^2)

6 0

3 years ago

Which expression is equivalent to the given expression 10q + 5

Mice21 [21]

<span>10q + 5 = 5q + 5q + 5

so
answer is
</span><span>
A. 5q+5q+5</span>

3 0

3 years ago

Read 2 more answers

An airplane started at point K, travelled 560 miles to point L, adjusted its route and travelled another 575 miles to point M. I

S_A_V [24]

Answer:

Step-by-step explanation:

Using the cosine theorem:

$c^{2} =a^{2} +b^{2} -abcos\beta$

$952^{2} =560^{2} +575^{2} -560*575cos\beta$

$\beta =cos^{-1} (\frac{560^{2}+575^{2}-952^{2} }{2*560*575} )$

The angle is 114.014 degrees if we substract 90 degrees it means that at point L the plane changed its angle by 24 degrees

4 0

3 years ago