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Cloud [144]
3 years ago
15

The local gym is advertising a special for new members: $10 to join and only $14.50 per month for the first year. If Salim joins

the gym for one year, how much will he spend on membership?
Mathematics
1 answer:
Anton [14]3 years ago
5 0

Answer:

$184

Step-by-step explanation:

$14.50 × 12 months = $174

$174 + $10 = $184

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Okay for this question the answer is x=0.
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Please help me! I will mark you brainliest!
AleksAgata [21]

Answer:

1

Step-by-step explanation:

8 0
3 years ago
What values of the variable cannot possibly be solutions for the given​ equation, without actually solving the​ equation? StartF
Advocard [28]

Answer: Hello mate!

our equation in this problem is:

\frac{6}{2x + 3} - \frac{1}{x - 7}  = 0

Now we have a rule in mathematics when the denominator is zero, the function is undefined (because you can not divide by zero). The two denominators that we have here are:

2x + 3 and x - 7, and now we can see for which values of x these denominators are zero in order to discard the values of x

1) 2x + 3 = 0

  x = -3/2 = -1.5

and

2) x - 7 = 0

   x= 7

(2x + 3); wich is equal to zero when x = -1.5 and x-7, wich is equal to zero when x = 7.

So just looking at these fractions you could assume that x = 7 and x= -1.5 are not possible solutions.

6 0
3 years ago
Solve 3n=42. Check your answer
charle [14.2K]

Answer: n=14

Equation being solved:  3n=42

Step 1. You need to first divide both sides by 3.

3n/3 = 42/3

n=14

Final answer: n=14

Hope this helps! :)


3 0
3 years ago
(HURRY, NO LINKS) Someone please, this is due today!! Ill give brainliest to decent answer, and 50+ points. !!
Tanya [424]

Answer:

Part A: the dependant variable is how many hours he works mowing lawns.

the independent variable is that she earns $7 per hour.

Part B:(1,7) 1 hour working for $7

(2,14) 2 hours working for $14

(3,21) 3 hours working for $21

Part C: Y=7h (h represents the number of hours she works)

Step-by-step explanation:

I'm not 100% sure about part A I have not done this in a while but here you go

hope this helps

4 0
3 years ago
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