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Varvara68 [4.7K]
2 years ago
15

Write the equation of the line that is parallel to the line y = 3x – 5 and passing

Mathematics
1 answer:
sergey [27]2 years ago
7 0
Y=3x+17

this passes through the point (-5,2) and is parallel to y=3x-5
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HELPP PLEASE ! This mapping shos a functional reationship.
Elina [12.6K]
The answer is 3 // The ones in blue are the domain and the ones in red are the range
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2 years ago
Tim is training for a marathon, He ran 24 miles in 5 days, if he ran the same distance each diay, how far did he run per day?
malfutka [58]

Answer:

I believe its 4.8, which is confusing seeing as its not an option.

Step-by-step explanation:

If he ran 24 miles in 5 days, divide 24 by 5 to get your answer.

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3 years ago
-13x>-26____________
Hitman42 [59]

Answer:

x<2

Step-by-step explanation:

-x>-2

x<2

It's the explanation

3 0
2 years ago
List the angles of triangle ABC in order from smallest to largest measure if AB = 9, AC = 11, and BC = 10.
galben [10]
Across smallest side- smallest angle.
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4 0
3 years ago
Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2
Ipatiy [6.2K]

Answer:

\frac{dAB}{dt}=340 mil/h

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here.  We can use the Pythagorean theorem, so the distance between the planes will be:

AB^{2} =AO^{2}+BO^{2} (1)

AB =\sqrt{AO^{2}+BO^{2}}=

AB =\sqrt{90^{2}+120^{2}}=150 miles

If we take the derivative of the equation (1) we could find the change of the distance between planes.

2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}

2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h

\frac{dAB}{dt}=\frac{102000}{150*2}

Finally,

\frac{dAB}{dt}=340 mil/h

I hope it helps you!

6 0
2 years ago
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