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Varvara68 [4.7K]
3 years ago
15

Write the equation of the line that is parallel to the line y = 3x – 5 and passing

Mathematics
1 answer:
sergey [27]3 years ago
7 0
Y=3x+17

this passes through the point (-5,2) and is parallel to y=3x-5
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8(3x - 4) = 4x - 2<br> What is x?
Serga [27]

Answer:

x=2/3

Step-by-step explanation:

8 (3x-4)= 4x-2

24x-32= 4x-2

20x=30

x=2/3

4 0
3 years ago
A rotating lawn sprinkler sprays water in a circular area of grass as shown in the picture. The diameter of the circular area of
Georgia [21]

Answer:

9\pi \: \mathrm{ft^2\:or}\: 28.27 \mathrm{\: ft^2}

Step-by-step explanation:

The area of a circle is given by r^2\pi where r is the radius of the circle. The diameter is given as 6 feet, so the radius of this circle is \frac{6}{2}=3 feet.

Plugging in our values, we get:

3^2\pi=9\pi\approx28.27.

7 0
3 years ago
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
Easy math problems!!!
neonofarm [45]

Answer:

Rad 68

Step-by-step explanation:

84- 4^2=68

7 0
3 years ago
Read 2 more answers
Please help. Thank you in advance.
ivolga24 [154]

Answer:

The second choice is the same so it is the last one

7 0
3 years ago
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