Answer:
x2-6=5x
Step-by-step explanation:
Answer:
x = 48 and y = 104
Step-by-step explanation:
Given equations are:

From equation 1:

Putting the value of y in equation 2

Now we have to put the value of y in one of the equation to find the value of x
Putting y = 104 in the first equation

Hence,
The solution of the system of equations is x = 48 and y = 104
The value of variable which was assumed for number of hats, is the total number of hats.
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
Answer:
6.
Step-by-step explanation:
1) OA=d/2=20/2=10;
2) AB=AC/2=16/2=8;
