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ki77a [65]
2 years ago
11

Prove algebraically that n^2-2-(n-2)^2 is always even

Mathematics
2 answers:
Juliette [100K]2 years ago
6 0

Answer:

It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)

Step-by-step explanation:

{n}^{2}  - 2 - ( {n}^{2}  + 4 - 4n) =  \\  {n}^{2}  - 2 - {n}^{2}   - 4  +  4n = \\ 4n - 6 = 2(2n - 3)

tresset_1 [31]2 years ago
3 0

Step-by-step explanation:

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