2 years ago

Prove algebraically that n^2-2-(n-2)^2 is always even

2 answers:

6 0

Answer:

It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)

Step-by-step explanation:

${n}^{2} - 2 - ( {n}^{2} + 4 - 4n) = \\ {n}^{2} - 2 - {n}^{2} - 4 + 4n = \\ 4n - 6 = 2(2n - 3)$

3 0

Step-by-step explanation:

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