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ki77a [65]
2 years ago
11

Prove algebraically that n^2-2-(n-2)^2 is always even

Mathematics
2 answers:
Juliette [100K]2 years ago
6 0

Answer:

It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)

Step-by-step explanation:

{n}^{2}  - 2 - ( {n}^{2}  + 4 - 4n) =  \\  {n}^{2}  - 2 - {n}^{2}   - 4  +  4n = \\ 4n - 6 = 2(2n - 3)

tresset_1 [31]2 years ago
3 0

Step-by-step explanation:

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tamaranim1 [39]
When eggs = 2, then potatoes = 5

Eggs: 2
Potatoes: 5

When that is changed to 6 eggs, 2 needs to be multiplied by a number to get 6.

2 * what = 6      or      6/2=

you get the number 3. A fraction is equivalent to a ratio. So if you have 2*3=6 then you need to multiply 5*3 to get the amount of potatoes you need. the answer is 15 potatoes because 5*3=15.
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3 years ago
Write a two-columm proof
Nastasia [14]

Both angles 2x+6 and 96 shown are vertically opposite angles and vertically opposite angles are always equal

so 2x+6 should be equal to 96

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So first get rid of +6 by doing its opposite -6 on both sides

2x + 6 -6 = 96 -6

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x = 45

Hence proved that x = 45

4 0
3 years ago
You buy 80 of your favorite songs from a Web site that charges ​$0.98 for each song. What is the cost of 80 ​songs? Use mental m
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3 years ago
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6 0
2 years ago
The area of the base (B) of a triangular pyramid is 28 cm. The perimeter (p) is 20 cm, and the slant height (S) is 5 cm. Determi
kenny6666 [7]

Answer:

The pyramid's surface area is 78 square centimeters

Step-by-step explanation:

The formula of the surface area of a pyramid is S.A = A + \frac{1}{2} p s, where

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  • p is the perimeter of its base
  • s is the slant height of it

∵ The area of the base of a triangular pyramid is 28 cm²

∴ A = 28 cm²

∵ The perimeter of the base is 20 cm

∴ p = 20 cm

∵ The he slant height is 5 cm

∴ s = 5 cm

- Substitute these values in the formula of the surface area

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∵ S.A = 28 + \frac{1}{2} (20)(5)

∴ S.A = 28 + 50

∴ S.A = 78 cm²

The pyramid's surface area is 78 square centimeters

5 0
3 years ago
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