Question

What value of x satisfies

Answer 1

Answer:

See explanation

Step-by-step explanation:

The given trigonometric equation is $cos(90-x)=-\frac{\sqrt{3} }{3}$.

We take the inverse cosine of both sides to get:

$90-x=cos^{-1}(-\frac{\sqrt{3} }{3})$

$90-x=125$

$x=125-90$

$x=-35\degree=325\degree$ to the nearest degree

None of the options satisfies the given equation.

But if the question is actually;

$cos(90-x)=-\frac{\sqrt{3} }{2}$

Then;

$90-x=\cos^{-1}(-\frac{\sqrt{3} }{2})$.

$90-x=210$.

$90-x=210$.

$x=-120\degree$.

Or

$x=360-120=240\degree$.

In this case the answer will be B

Answer 2

Answer:

the correct answer is 150

Step-by-step explanation:

i j took the test