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Arada [10]
3 years ago
13

Patti has two glue sticks that are partially used . One has 1/5 left and one has 3/10 left. Which glue stick has more glue

Mathematics
2 answers:
maxonik [38]3 years ago
8 0

Answer:

The one with 3/10 left has more

Step-by-step explanation:

Compare the two numbers.  Use a common denominator of 10,

1/5 = (1*2)/(5*2)           we multiplied by 2/2, which is 1, so the value is the same

   (1*2)/(5*2) = 2/10  

2/10 is less than 3/10, so the glue stick with 3/10 left has more

leonid [27]3 years ago
5 0

Answer:

The second glue stick

Step-by-step explanation:

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A person whose eye level is 15 feet above the ground is looking at a building. The angle of elevation to the top of the building
uysha [10]

Answer:

61.97 feets

Step-by-step explanation:

Using trigonometry :

Horizontal distance between the person and building,

Let distance = d

Tan 15 = 15 / d

0.2679491 * d = 15

d = 15 / 0.2679491

d = 55.980781

To obtain the height, h :

tan 40 = (h-15)/d

d = 55.98

h-15 = 55.98 (tan 40°)

h - 15 = 55.98 * 0.8390996

h - 15 = 46.972797

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3 years ago
What number should be placed in the box to help complete the division calculation?
joja [24]
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A dog jumps straight up in the air to catch a ball and lands on the ground 1.3 s later. Let h(t) represent the dog’s height, in
slamgirl [31]

The given question have mistake. The correct question is written below.

Question:

A dog jumps straight up in the air to catch a ball and lands on the ground 6.37 s later. Let h(t) represent the dog’s height, in meters, t seconds after he leaves the ground. Which equation models the dog’s height for a given time t?

Answer:

Option B:

h(t)=-4.9 t^{2}+6.37t

Solution:

<u>General formula for the height of the projectile over time:</u>

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(2) h(t)=-4.9 t^{2}+v t+s

Where h = height in meters, t = time, v = initial velocity and s = initial height(meter)

Given initial velocity = 6.37 s and initial height is 0.

The height of the dog is in meters.

So, use second formula and substitute v = 6.37 and s = 0.

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h(t)=-4.9 t^{2}+6.37t+0

h(t)=-4.9 t^{2}+6.37t

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6 0
3 years ago
which of the following equations can be used to calculate the values of t for which the distance between Chris and any is 300 mi
Papessa [141]
The first thing we must know in this case is that the distance is equal to the speed for time.
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