Explanation:
When neutral objects are placed in the vicinity of charged objects,they get attracted.
The isolated neutral object has positive charge and negative charge spread throughout it completely.
When a charged particle is brought,the opposite charges in the neutral object occupy the positions near to the charged particle and the like charges occupy the positions far from the charged particle.
This creates a dipole with some dipole moment.
This dipole attracts to the field of the charged particle.
Answer:
|A| = √(Ax)^2 + (Ay)^2
|A| = √(7.6)^2 + (-6.4)^2
|A| = √98.72
|A| = 9.9
Answer:
3.222 ohms
Explanation:
If the total wire had a resistance of 29 ohms, when cut in three, each piece will have a resistance of 9.666 ohms.
As these three pieces (R1, R2 and R3) are now connected in parallel, the equivalent resistance R can be calculated using this equation:
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/9.666 + 1/9.666 + 1/9.666
1/R = 3/9.666
R = 9.666/3 = 3.222 ohms
The resistance between A and B will be 3.222 ohms
........................................................................................
Answer:
2N
Explanation:
Given that a student pulls down with a force of 40 N on a rope that winds around a pulley of radius 5 cm. find the torque?
Solution
Using the formula
Torque = Force × radius
I.e
Torque = F r
Where
F = 40N
r = 5 cm = 5/100 = 0.05m
Substitute all the parameters into the formula
Torque = 40 × 0.05
Torque = 2 N
Therefore, the torque on this scenario is 2 N
