Answer:
x₂=0.44m
Explanation:
First, we calculate the length the spring is stretch when the first block is hung from it:
Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:
Solving for the spring constant k, we get:
Next, we use the same relationship, but for the second block, to find the value of the stretched length:
Finally, we sum this to the unstretched length to obtain the length of the spring:
In words, the length of the spring when the second block is hung from it, is 0.44m.
Without friction, the amount of work only depends on the final height,
and is not affected by the route used to get there.
If the ramp has no friction, then it has no effect on the total amount
of work done. The work to lift the load straight up is the same.
If the ramp has some friction, then it takes more work to use the ramp
than to lift the load straight up. Then the work to lift the load straight up
would be less than when the ramp is used.
Answer:
Distance: 4.6km Displacement= -0.2km
Explanation:
Total distance: 1.5+2.4+0.7= 4.6 km
Displacement: 1.5-2.4+0.7= -0.2km
The displacement may also be 0.2km, it just depends on if it wants it negative or not.
Answer:
The density of balsa wood is about 170 kg/m^3.
Explanation:
happy to help :)
Answer:
The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
Explanation:
We can find the drift speed by using the following equation:
Where:
I: is the current = 4.50 A
n: is the number of electrons
q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C
A: is the cross-sectional area = 2.20x10⁻⁶ m²
We need to find the number of electrons:
Now, we can find the drift speed:
Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
I hope it helps you!
