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3 years ago

An airplane flies at 100km/h in still air. If it flies into a 10 km/h headwind, its groundspeed is

Physics

2 answers:

HACTEHA [7]3 years ago

5 0

Answer:

D) $90\frac{km}{h}$

Explanation:

The groundspeed of the airplane is equal to the speed of the airplane in still air, plus the speed of the air. Since the plane flies with headwind, the sign of the air speed is negative, since it is contrary to the movement of the airplane.

Now, we have:

$V_g=V_a+V_h$

Here $V_g$ is the airplane groundspeed, $V_a$ the airplane speed and $V_h$ the air speed

$V_g=100\frac{km}{h}+(-10\frac{km}{h})=90\frac{km}{h}$

timama [110]3 years ago

3 0

Its D.) 100-10 is 90 the plane is flying in the 10 km/h wind at 100 km/h take away the resistance and you get your ground speed

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A 70mm long blockhas cross-section of 50mm by 10mm the block is subjected to forces 60KN (tension) on the 50mm by 10mm face and

sammy [17]

Answer:

970 kN

Explanation:

The length of the block = 70 mm

The cross section of the block = 50 mm by 10 mm

The tension force applies to the 50 mm by 10 mm face, F₁ = 60 kN

The compression force applied to the 70 mm by 10 mm face, F₂ = 110 kN

By volumetric stress, we have that for there to be no change in volume, the total pressure applied by the given applied forces should be equal to the pressure removed by the added applied force

The pressure due to the force F₁ = 60 kN/(50 mm × 10 mm) = 120 MPa

The pressure due to the force F₂ = 110 kN/(70 mm × 10 mm) = 157.142857 MPa

The total pressure applied to the block, P = 120 MPa + 157.142857 MPa = 277.142857 MPa

The required force, F₃ = 277.142857 MPa × (70 mm × 50 mm) = 970 kN

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3 years ago

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Lostsunrise [7]

Answer:

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3 years ago

Calculate the Poynting vector at the surface of the filament, associated with the static electric field producing the current an

Vesnalui [34]

We anticipate a constant Poynting vector of magnitude since the hot resistor will be emitting heat and none of the electric or magnetic fields will change over time.

S = P/A

= I2R/ 2πrL

= 332 kW/m2

Always pointing away from the wire, this Poynting vector.

<h3>What is the Poynting vector?</h3>

Describes the size and direction of the energy flow in electromagnetic waves using a Poynting vector. It bears the name of the 1884 invention of English physicist John Henry Poynting. It stands for the electromagnetic field's directional energy flux or power flow. The Poynting vector is significant in a static electromagnetic field because it determines the direction of energy flow in an electromagnetic field. This vector represents the radiation pressure of an electromagnetic wave and points in its direction of propagation.

To learn more about Poynting vector, visit:

<u>brainly.com/question/17330899</u>

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3 years ago

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A straight segment of wire has a length of 25 cm and carries a current of 5A. If the wire is perpendicular to the magnetic field

Irina-Kira [14]

Answer:

The magnitude of the magnetic force acting on the conductor is 0.75 Newton

Explanation:

The parameters given in the question are;

The length of the straight segment of wire, L = 25 cm = 0.25 m

The current carried in the wire, I = 5 A

The orientation of the wire with the magnetic field = Perpendicular

The strength of the magnetic field in which the wire is located, B = 0.60 T

The magnetic force, 'F', is given by the following formula;

F = $\underset{I}{\rightarrow }$ ·L× $\underset{B}{\rightarrow }$ = I·L·B·sin(θ)

Where;

$\underset{I}{\rightarrow }$ = The current flowing, I

L = The length of the wire

$\underset{B}{\rightarrow }$ = The magnetic field strength, B

θ = The angle of inclination of the conductor to the magnetic field

Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;

F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N

Therefore

The magnitude of the magnetic force, F = 0.75 N.

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3 years ago